If x + 1 x 4 then the value of x 2 + 1 x 2 is
WebMathematics If x 2 + y 2 = 9 and xy = 8, then x + y is equal to 25 5 -5 ±5 Expansions ICSE 1 Like Answer We know that, (x + y) = \sqrt {x^2 + y^2 + 2xy} (x+y)= x2 +y2 + 2xy. Substituting values we get, (x + y) = \sqrt {9 + 2 \times 8} = \sqrt {9 + 16} = \sqrt {25} = \pm 5 (x+y)= 9+2× 8 = 9+16 = 25 = ±5. Hence, Option 4 is the correct option. WebThe signum function is the derivative of the absolute value function, up to (but not including) the indeterminacy at zero. More formally, in integration theory it is a weak derivative, and …
If x + 1 x 4 then the value of x 2 + 1 x 2 is
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Web22 mrt. 2024 · Transcript Example 1 If (x + 1, y – 2) = (3, 1), find the values of x and y. (x + 1, y – 2) = (3, 1) Since the ordered pairs are equal, corresponding elements are equal. … Web10 apr. 2024 · Characterization of birnessite-biochar composite electrode. The XRD patterns of BC-Mn are shown in Fig. 1a. The angles of 12.3°, 24.1°, 37.1° and 65.9° correspond …
WebSolution In the given problem, we have to find the value of x + 1 x Given x - 1 x = 15 4 We shall use the identity ( a - b) 2 = a 2 + b 2 - 2 a b Here putting x - 1 x = 15 4, ( x - 1 x) 2 = … WebIf 4 x−4 x−1=24, then (2x) x equals A 25 B 125 C 5 D 255 Medium Solution Verified by Toppr Correct option is D) 4 x−4 x−1=24 or 4 x(1− 41)=24 or 4 x43=24 or 4 x= …
Web30 mrt. 2024 · Ex 2.2, 15 If tan−1 (x − 1)/ (x − 2) + tan−1 (x + 1)/ (x + 2) = 𝜋/4 , then find the value of x. Given tan−1 ( (𝐱 − 𝟏)/ (𝐱 − 𝟐)) + tan−1 ( (𝐱 + 𝟏)/ (𝐱 + 𝟐)) = 𝜋/4We know that tan−1 x + … Web23 mrt. 2024 · If 10^x is 4, find the value of 10^(2x+1). Pinoybix exponential function problem solving and math review materials. Menu. New! ECE. Math. ... Solution: If 16 is …
Web30 apr. 2024 · It is given that , x + 1/x = 4 --- ( 1 ) Do the square of equation ( 1 ), ( x + 1/x )² = 4² x² + 1/x² + 2 = 16 x² + 1/x² = 16 - 2 x² + 1/x² = 14 -- ( 2 ) Again do the square of equation ( 2 ), ( x² + 1/x² )² = 14² x⁴ + 1/x⁴ + 2 = 196 x⁴ + 1/x⁴ = 196 - 2 = 194 I hope this helps you. :) Advertisement prataprathor2008 Step-by-step explanation:
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